s^2-13s+12=0

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Solution for s^2-13s+12=0 equation:


Simplifying
s2 + -13s + 12 = 0

Reorder the terms:
12 + -13s + s2 = 0

Solving
12 + -13s + s2 = 0

Solving for variable 's'.

Factor a trinomial.
(1 + -1s)(12 + -1s) = 0

Subproblem 1

Set the factor '(1 + -1s)' equal to zero and attempt to solve: Simplifying 1 + -1s = 0 Solving 1 + -1s = 0 Move all terms containing s to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1s = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1s = 0 + -1 -1s = 0 + -1 Combine like terms: 0 + -1 = -1 -1s = -1 Divide each side by '-1'. s = 1 Simplifying s = 1

Subproblem 2

Set the factor '(12 + -1s)' equal to zero and attempt to solve: Simplifying 12 + -1s = 0 Solving 12 + -1s = 0 Move all terms containing s to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + -1s = 0 + -12 Combine like terms: 12 + -12 = 0 0 + -1s = 0 + -12 -1s = 0 + -12 Combine like terms: 0 + -12 = -12 -1s = -12 Divide each side by '-1'. s = 12 Simplifying s = 12

Solution

s = {1, 12}

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